When i click on button to show the message i get one MessageBox that's normal but when i call the Jquery Dialog for the SCOND time i get two MessageBoxs! and when i call Jquery Dialog for the third time i get three MessageBoxs!
Why when i click on an asp.net button inside the jquery Dialog the function is repeated ?
Please help me!
Here is my Code:
<%@ Page Language="C#" AutoEventWireup="true" CodeFile="Default.aspx.cs" Inherits="_Default" %>
<!DOCTYPE html>
<html xmlns="http://www.w3.org/1999/xhtml">
<head runat="server">
<title></title>
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.7.2/jquery.min.js"></script>
<script src="http://ajax.aspnetcdn.com/ajax/jquery.ui/1.8.9/jquery-ui.js" type="text/javascript"></script>
<link href="http://ajax.aspnetcdn.com/ajax/jquery.ui/1.8.9/themes/start/jquery-ui.css"
rel="stylesheet" type="text/css" />
<script type="text/javascript">
$(document).ready(function () {
$("[id*=Call_Dialog]").click(function() {
$("#MyDiv").dialog({
title: "jQuery Dialog Popup",
buttons: {
Close: function () {
$(this).dialog('close');
}
}
});
$("#ShowMessage").click(function () {
event.preventDefault();
alert('Hi');
$("#MyDiv").dialog('close');
})
})
});
</script>
</head>
<body>
<form id="form1" runat="server">
<div id="MyDiv" style="display: none">
<asp:Button ID="ShowMessage" runat="server" Text="Button" />
</div>
</form>
<p>
<input id="Call_Dialog" type="button" value="button" /></p>
</body>
</html>
