Display Icon in LinkButton inside ASP.Net GridView based on condition using Font Awesome

Hi wxlf960,

Check this example. Now please take its reference and correct your code.

HTML

<link rel="stylesheet" href="https://cdnjs.cloudflare.com/ajax/libs/font-awesome/4.7.0/css/font-awesome.min.css" />
<link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.2/css/bootstrap.min.css" />
<asp:GridView ID="GridView1" runat="server" AutoGenerateColumns="false">
    <Columns>
        <asp:BoundField DataField="Name" HeaderText="Name" />
        <asp:TemplateField>
            <ItemTemplate>
                <asp:LinkButton runat="server" OnClick="lnk1_Click"
                    Text='<%# Eval("absentee").ToString() == "1" ? 
                        "<i class=\"fa fa-check\"></i> Yes" : 
                        "<i class=\"fa fa-times\"></i> No" %>'></asp:LinkButton>
            </ItemTemplate>
        </asp:TemplateField>
    </Columns>
</asp:GridView>

Code

protected void Page_Load(object sender, EventArgs e)
{
    if (!this.IsPostBack)
    {
        DataTable dt = new DataTable();
        dt.Columns.AddRange(new DataColumn[3] {
            new DataColumn("Id"),
            new DataColumn("Name"),
            new DataColumn("absentee") });
        dt.Rows.Add(1, "John Hammond", "1");
        dt.Rows.Add(2, "Mudassar Khan", "0");
        dt.Rows.Add(3, "Suzanne Mathews", "0");
        dt.Rows.Add(4, "Robert Schidner", "1");
        GridView1.DataSource = dt;
        GridView1.DataBind();
    }
}

protected void lnk1_Click(object sender, EventArgs e)
{

}

Screenshot