SELECT records with Group By by selecting MAX value in SQL Server Query

Please refer below scirpt.

SQL

DECLARE @temp AS TABLE([identity] INT IDENTITY(1,1),UserID  INT,UpdatedDate DATETIME)

INSERT INTO @temp VALUES
(1,'2015/08/15'),
(2,'2015/08/18'),
(2,'2015/08/09'),
(1,'2015/08/21'),
(3,'2015/08/22')

SELECT DISTINCT (SELECT TOP 1 [identity]  
			     FROM @temp tInner 
				 WHERE tInner.UpdatedDate = MAX(tOuter.UpdatedDate) 
				 AND tInner.UserID = tOuter.UserID
				 ) [Identity] 
			   ,UserID
               ,MAX(UpdatedDate) as UpdatedDate
FROM @temp tOuter 
GROUP BY UserID 
ORDER BY 3 DESC

Screenshot