In this article I will explain with an example, how to pass (send) Model object in jQuery $.ajax() POST request to Controller method in ASP.Net MVC 5 Razor.
The Controller action method will be called using jQuery AJAX $.ajax() POST request and the Model class object will be passed as JSON object from View in ASP.Net MVC 5 Razor.
Note: For beginners in ASP.Net MVC, please refer my article ASP.Net MVC Hello World Tutorial with Sample Program example.
 
 
Model
Following is a Model class named PersonModel with two properties i.e. Name and DateTime.
public class PersonModel
{
    ///<summary>
    /// Gets or sets Name.
    ///</summary>
    public string Name { get; set; }
 
    ///<summary>
    /// Gets or sets DateTime.
    ///</summary>
    public string DateTime { get; set; }
}
 
 

Controller
The Controller consists of two Action methods.
Action method for handling GET operation
Inside this Action method, simply the View is returned.
 
Action method for handling jQuery AJAX operation
This Action method handles the call made from the jQuery AJAX function from the View.
Note: The following Action method handles AJAX calls and hence the return type is set to JsonResult.
 
The PersonModel object which is passed from View is received as parameter. The Current DateTime value is assigned to the DateTime property and finally the same PersonModel object is returned back as JSON to the jQuery AJAX function.
public class HomeController : Controller
{
    // GET: Home
    public ActionResult Index()
    {
        return View();
    }
 
    [HttpPost]
    public JsonResult AjaxMethod(PersonModel person)
    {
        person.DateTime = DateTime.Now.ToString();
        return Json(person);
    }
}
 
 
View
Inside the View, in the very first line the PersonModel class is declared as Model for the View. The View consists of an HTML TextBox element and a Button. The Button has been assigned a jQuery click event handler and when the Button is clicked a jQuery AJAX called is made to the Controller’s action method.
The URL for the jQuery AJAX call is set to the Controller’s action method i.e. /Home/AjaxMethod. A JSON object named Person is created and the value of the TextBox is assigned to the Name property.
The Person JSON object is passed as parameter and the returned response is displayed using JavaScript Alert Message Box.
@model jQuery_AJAX_Model_MVC.Models.PersonModel
 
@{
    Layout = null;
}
 
<!DOCTYPE html>
 
<html>
<head>
    <meta name="viewport" content="width=device-width"/>
    <title>Index</title>
</head>
<body>
    <input type="text" id="txtName"/>
    <input type="button" id="btnGet" value="Get Current Time"/>
    <script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.8.3/jquery.min.js"></script>
    <script type="text/javascript" src="http://ajax.cdnjs.com/ajax/libs/json2/20110223/json2.js"></script>
    <script type="text/javascript">
        $(function () {
            $("#btnGet").click(function () {
                var person = {};
                person.Name = $("#txtName").val();
                $.ajax({
                    type: "POST",
                    url: "/Home/AjaxMethod",
                    data: '{person: ' + JSON.stringify(person) + '}',
                    contentType: "application/json; charset=utf-8",
                    dataType: "json",
                    success: function (response) {
                        alert("Hello: " + response.Name + ".\nCurrent Date and Time: " + response.DateTime);
                    },
                    failure: function (response) {
                        alert(response.responseText);
                    },
                    error: function (response) {
                        alert(response.responseText);
                    }
                });
            });
        });
    </script>
</body>
</html>
 
 
Screenshot
Pass (Send) Model object in jQuery $.ajax() POST request to Controller method in ASP.Net MVC
 
 
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